Question

pls solve it and keep attachment​

Answer 1

Answer:

Amount of energy released is 5.625 × 10²⁹ MeV

Given

Δm = 1.0 Kg

c = 3 × 10⁸ m/s

Amount of energy released

Einstein's mass energy equivalence :

E = (Δm)c²

Where :

E = Energy released/absorbed

m = mass of particle

c = speed of light

Substituting,

1.0 × (3 × 10⁸)²

9 × 10¹⁶ joule

Since,

1 MeV = 1.6 × 10⁻¹³ joule

MeV - mega electron volt

Substituting,

9 × 10¹⁶/1.6 × 10⁻¹³ MeV

5.625 × 10²⁹ MeV

∴ Amount of energy released is 5.625 × 10²⁹ MeV

Answer 2

Answer:

E=mc

2=1×(3×10 8) 2=9×10 ^16 J

The energy produced when 1 kg of a substance is fully converted into energy is 9×10

16

J.

Explanation:

PLS mark as brainlist