PLS SOLVE THE BELOW ATTACHMENT OF LINEA EQUATION IN ONE VARIABLE AND CO-ORDINATE GEOMETRY
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Answer:
By now, it should be evident that the general equation of a line has an x term, a y term and a constant term, so that we can write it as follows:
ax+by+c=0ax+by+c=0
We have also seen this form in the chapter on two-variable linear equations. Note that at least one of a and b must be non-zero.
We can convert any form of the line’s equation into the general form. For example, consider a line which passes through (1,3)(1,3) and has the slope −2−2. Using the point-slope form, the equation of this line is:
y−3=−2(x−1)⇒y−3=−2x+2y−3=−2(x−1)⇒y−3=−2x+2
We can rearrange this and write this in the general form as follows:
2x+y−5=02x+y−5=0
The general form of a line’s equation is also known as the standard form.
Example 1: Write the equation of the line passing through the points (−1,3)(−1,3) and (2,−3)(2,−3) in standard form.
Solution: Using the two-point form, the equation of the line is
y−y1x−x1=y2−y1x2−x1⇒y−3x−(−1)=−3−32−(−1)⇒y−3x+1
Answer:
check the above mentioned answer