Math, asked by ritam73, 11 months ago

pls solve the question no c​

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Answered by anu012
0

a)x^4+3x^2-2x

differentiate

=4x^3+6x-2=0

b)x^2cosx

differentiate

-2xsinx

c)(6x+7)^4

differentiate

4(6x+7)^3

d)e^x×x^5

differentiate

x^5=5x^4

e)1+x/e^x

differentiate

1+x=x+1=1

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Answered by diwanamrmznu
4

SOLUTION:-

 \implies  \frac{d}{dx} (6x + 7) {}^{4}  \\  \\  \implies \:  \frac{d}{dx} (6x + 4) {}^{4 - 1} .  \frac{d}{dx} (6x + 4) \\  \\  \implies \: (6x + 4) {}^{3} .(6 + 0) \\  \\  \implies \: 6(6x + 4) {}^{3}  \\

uses formula

 \implies  \star\pink{ \frac{d}{dx}x {}^{n} = nx  {}^{n - 1} } \\

 \implies  \star\pink{ \frac{d}{dx}a =0 } \\

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thank you

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