Question

Pls solve this ASAP.. ​

Answer 1

Answer:

$\frac{ |x| + 4}{ |x| + 4} = 1 \: \\ now \: we \: know \: that \: x \: is \: not \: negative \: as \: |x| \: cannot \: be \: negativeso \: as \: x + 3 \: is \: less \: than \: x + 4 \: \frac{x + 4}{x + 3} \: is \: greater \: than \: \frac{x + 4}{x + 4} \: so \: \frac{x + 4}{x + 4} > 0 \: so \: \frac{x + 4}{x + 3} > 0$

Hence proved.

Sorry just turn the formula to see full explanation. Sorry for inconvenience.

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