Question

Pls solve this question.....

Answer 1

Answer:

Step-by-step explanation:

IN ΔBCD AND ΔABD

∠BCA = ∠BAD (90°)

∠CBA = ∠DBA (COMMMON)

BY AA SIMILIARITY

BOTH TRIANGLES ARE SIMILAR

ΔBCD≈ΔABD

AB/BC=BD/AB

AB² = BD X BC

HENCE PROVED

Answer 2

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