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Step-by-step explanation:
IN ΔBCD AND ΔABD
∠BCA = ∠BAD (90°)
∠CBA = ∠DBA (COMMMON)
BY AA SIMILIARITY
BOTH TRIANGLES ARE SIMILAR
ΔBCD≈ΔABD
AB/BC=BD/AB
AB² = BD X BC
HENCE PROVED
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hey mate
Mark me a brainlist answer
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