Question

Pls some one help me with this now fast pls
I whant only the mole sum

Answer 1

i)Gram molecular mass of KOH= 39+16+1=56 amu

Mass of KOH= 4g

No. of Moles = Given mass/ Gram molecular mass
                     = 4/56 = 1/14 moles.

ii)No of moles of Mg = Given mass/ Gram molecular mass 
                                 =48/ 24
                                 = 2moles

No of particles = No. of moles x Avogadro's number

                       = 2 x 6.023x 10^23
                       = 12.046 x 10^23 particles

I Hope my answer is clear to u.