Question

pls tell the answer ​

Answer 1

Answer:

hope it will be helpful

Mark me brainliest

Answer 2

a+5d = 5a

a+10d = 2(a+4d)+3

Now you can find a and d, and then a+7d.

"The sixth term of an A.P. is 5 times the first term"

---> a+ 5d = 5a or 5d = 4a

a = 5d/4

"eleventh term exceeds twice the fifth term by 3"

term(11) -2 term(5) = 3

a + 10d - 2(a + 4d) = 3

-a + 2d = 3

-5d/4 + 2d = 3

times 4

-5d + 8d = 12

d = 4

then a = (5/4)(4) = 5

check:

term6 = a + 5d = 25 which is 5 times the first term

term 11 = a+10d = 45

twice term5 = 2(21) = 42 , which is 3 less than term11

term8 = a + 7d = 5 + 28 = 33.