Math, asked by harishdevkishan, 1 year ago

plss help me solve these 2 questions:

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harishdevkishan: Pls guys....help me....I need it soon
harishdevkishan: The one who will ans it correctly....a thanks advance from me and will marked as the brainliest

Answers

Answered by parisakura98pari
1
1) secx = m² + n² /2mn
cosx = 2mn/ m² + n²                  sinx = m-n / m²+n²

tanx = m-n/2mn

√1 + sinx / √1- sinx =    rationalizing ====  √(1+sinx)²/√1 - sin²x
⇒ (1+sinx)/ cosx ===== secx + tanx ======= m² + n² +m - n /2mn

2)  just put x = 60° 

sin60/sec60  + tan60 -1     +   cos60 / cosec60 + cot60 - 1
⇒ √3/2 / 2 + √3 - 1            +    1/2 /  2/√3 + 1/√3 -1

⇒ √3/2 / 1 + √3             +      1/2 / √3 - 1
⇒ √3(√3 - 1) + 1 + √3   /  2 (√3² - 1² )
⇒ 3 - √3 + 1 +√3 / 2 (3-1) =  4 / 2(2) = 1

hope  u'll    get it ..if doubt then ask  
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