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Let one root be a.
So, a+a²=-p and a.a²=q
Now eliminate a and get a relation in p and q.
So, a+a²=-p and a.a²=q
Now eliminate a and get a relation in p and q.
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Let one root be x then other must be x² . then x+x²= –p and x³=q . as we have to find the relation in terns of p³ . then in the relation of sum of roots. Take cube both sides. And put the respective value of x³. U will get the ans. Hope it helped.
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Let one root be x then other must be x² . then x+x²= –p and x³=q . as we have to find the relation in terns of p³ . then in the relation of sum of roots. Take cube both sides. And put the respective value of x³. U will get the ans. Hope it helped.
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