Math, asked by aakankshabharadwaj29, 9 months ago

Solve 8x^2− 22x − 21 = 0 by the factorization method​

Answers

Answered by hellboy44
1

Answer:

two zeroes of this equation are -3/4 and7/2.

Step-by-step explanation:

8x²-22x-21

=8x²-28x+6x-21

=4x(2x-7)+3(2x-7)

=(4x+3)(2x-7)

Therefore 4x+3=0

4x=-3

x=-3/4

2x-7=0

2x=7

x=7/2

Answered by Anonymous
2

{\sf{\tt{\boxed{\purple{\underline{\underline{\huge{Answer:}}}}}}}}

\implies\sf {8x}^{2} - 22x - 21 = 0

\implies\sf {8x}^{2} - 28x + 6x - 21 = 0

\implies\sf4x(2x - 7) + 3(2x - 7) = 0

\implies\sf(4x + 3) = 0 \:  \: or \:  \: (2x - 7) = 0

\implies\sf4x =  - 3 \:  \: or \:  \: 2x = 7

\implies\sf \: x =  -  \dfrac{3}{4} \:  \: or \:  \: x =  \dfrac{7}{2}

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