Question

plz ans the numerical..................

Answer 1

0.49 is answer .

Explanation:

Potential remains same in the resistors when they are connected in the parallel.

∴ Potential in both the bulbs will be same.

Now,

For First Tungsten Bulb,

Power = 50 W.

Potential = 220 V

∵ Power = Potential × Current.

∴ Current = 50/220

Current = 0.22 A

For second Tungsten bulbs,

Power = 60 W.

Potential = 220 V.

∴ Current = 60/220

= 0.27 A

Now, Total current flowing = Current in 1st bulb + Current in 2nd bulb.

= 0.22 + 0.27

= 0.49 A

Hence, the total current flowing in the main conductor is 0.49 A

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