plz answer 6 to 11 questions
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uspc jain public school
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Answer No. 6
Draw Triangle ABC
AC=20 cm (Hypotenuse)
BC= 15 cm ( Base)
To find (AB)²(Perpendicular)
Using Pythagoras Theorem
(Hy)²= (Per.)²+ (Base)²
(AC)²= (AB)²+ (BC)²
(20)²= (AB)²+ (15)²
400= (AB)²+225
(AB)²= 400-225=175 cm
Answer No. 7 = Sum of Supplementary Angles are 180°
The Angles Are in the ratio of 4:5
4x and 5x
Sum of Supplementary angles=180°
4x+5x= 180°
9x= 180°
x= 180°/9=20°
4x = 20× 4=80°
5x = 5× 20 = 100°
Draw Triangle ABC
AC=20 cm (Hypotenuse)
BC= 15 cm ( Base)
To find (AB)²(Perpendicular)
Using Pythagoras Theorem
(Hy)²= (Per.)²+ (Base)²
(AC)²= (AB)²+ (BC)²
(20)²= (AB)²+ (15)²
400= (AB)²+225
(AB)²= 400-225=175 cm
Answer No. 7 = Sum of Supplementary Angles are 180°
The Angles Are in the ratio of 4:5
4x and 5x
Sum of Supplementary angles=180°
4x+5x= 180°
9x= 180°
x= 180°/9=20°
4x = 20× 4=80°
5x = 5× 20 = 100°
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