Question

plz answer asap
need it for my exams
in the figure,D is a point on BC such that angle ABD...
2 A(∆ACD):A(∆BCA)​

Answer 1

(i) In triangle ABC

AC^2+BC^2=BA^2(Pythagoras theorem)

3^2+BC^2=5^2

9+BC^2=25

BC^2=25-9

BC=√16

BC=4cm

in triangle ADC,

AD^2=DC^2+CA^2

4^2=3^2+AC^2

16-9=AC^2

AC=√7

AC=2.64

(ii) ar(∆ACD):ar(∆BCA)

(1/2*3*2.64):(1/2*3*4)

3.96:6

=1.32:2

Hope it helps you