plz answer fast with correct answer and detailed solution
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the answer is b .. i don't have energy to solve and show everything
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Answer:
Sn=An²+Bn
S1=A(1)²+B(1)=A+B
S2=A(2)²+B(2)= 4A+2B
S3=A(3)³+B(3)=9A+3B
A+B, 3A+B,5A+B....
a=A+B
=>d=2A
nth
Tn=a+(n-1)=(A+B)+(n-1)
=>Tn=A(2n-1)+B
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