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given:PQ perpendicular to AB
PR perpendicular to BC
PQ=2
BP is bisector of angle B
to find :PR
proof:
in triangle QPB and triangle RPB
angleR=angleO(each 90°)
angleQBP=angleRBP(asBP is bisector)
BP=BP(common)
triangleQPB is congruent to triangle RPB by AAS
PR=PQ by cpct
PR=2=PQ
PLZ MARK IT BRAINLIEST
PR perpendicular to BC
PQ=2
BP is bisector of angle B
to find :PR
proof:
in triangle QPB and triangle RPB
angleR=angleO(each 90°)
angleQBP=angleRBP(asBP is bisector)
BP=BP(common)
triangleQPB is congruent to triangle RPB by AAS
PR=PQ by cpct
PR=2=PQ
PLZ MARK IT BRAINLIEST
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