Plz answer my question fast plz
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Step-by-step explanation:
in∆ABC,
angle C +Angle A+ Angle B=180°
90°+40°+<B=180°
<B=180-130
<B=50°
in ∆EDC<E+<D+<B=180°
100°+x+50°=180°
x =30°
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