plz answer no. 6 question
Attachments:
Answers
Answered by
1
Solution :
![{\tan }^{ - 1} \left[ 2 \sin \left(2 \: {\cos }^{ - 1} \frac{ \sqrt{3} }{2} \right) \right ] \\ \\ = { \tan }^{ - 1} \left[ 2 \sin \left(2 \times \frac{\pi}{6} \right) \right ] \\ \\ = {\tan }^{ - 1} \left( 2 \sin \frac{\pi}{3} \right ) \\ \\ = {\tan}^{ - 1} \left(2 \times \frac{ \sqrt{3} }{2} \right) \\ \\ = {\tan }^{ - 1} \left( \sqrt{3} \right) \\ \\ = \frac{\pi}{3} \: \: \: \: \: \: \: \textbf{Ans.}](https://tex.z-dn.net/?f=%7B%5Ctan++%7D%5E%7B+-+1%7D+%5Cleft%5B+2+%5Csin+%5Cleft%282+%5C%3A++%7B%5Ccos+%7D%5E%7B+-+1%7D+++%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D++%5Cright%29+++%5Cright+%5D+%5C%5C++%5C%5C+%3D+%7B+%5Ctan+%7D%5E%7B+-+1%7D++%5Cleft%5B+2+%5Csin+%5Cleft%282+++%5Ctimes++%5Cfrac%7B%5Cpi%7D%7B6%7D++%5Cright%29+++%5Cright+%5D+%5C%5C++%5C%5C++%3D+%7B%5Ctan++%7D%5E%7B+-+1%7D+%5Cleft%28+2+%5Csin++%5Cfrac%7B%5Cpi%7D%7B3%7D++++%5Cright+%29+%5C%5C++%5C%5C++%3D++%7B%5Ctan%7D%5E%7B+-+1%7D++%5Cleft%282+%5Ctimes++%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D++%5Cright%29++%5C%5C++%5C%5C+++%3D++%7B%5Ctan+%7D%5E%7B+-+1%7D++%5Cleft%28+%5Csqrt%7B3%7D++%5Cright%29+%5C%5C++%5C%5C++%3D+%5Cfrac%7B%5Cpi%7D%7B3%7D++%5C%3A+++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+%5Ctextbf%7BAns.%7D "{\tan }^{ - 1} \left[ 2 \sin \left(2 \: {\cos }^{ - 1} \frac{ \sqrt{3} }{2} \right) \right ] \\ \\ = { \tan }^{ - 1} \left[ 2 \sin \left(2 \times \frac{\pi}{6} \right) \right ] \\ \\ = {\tan }^{ - 1} \left( 2 \sin \frac{\pi}{3} \right ) \\ \\ = {\tan}^{ - 1} \left(2 \times \frac{ \sqrt{3} }{2} \right) \\ \\ = {\tan }^{ - 1} \left( \sqrt{3} \right) \\ \\ = \frac{\pi}{3} \: \: \: \: \: \: \: \textbf{Ans.}")
SB07:
i hv another question
Similar questions
English,
7 months ago
Psychology,
7 months ago
Social Sciences,
1 year ago
Biology,
1 year ago
Biology,
1 year ago