plz answer quickly..solve the following quadratic equation
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Here is your answer it may help..
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Hey !
★ Here is your answer ★
__________________________
--> [ 2x + 3 ]^2 = 25
----> 4x2 + 9 + 2 [ 2x × 3 ] = 25
---> 4x2 + 9 + 12x - 25 = 0
---> 4x2 + 12x - 16 = 0
---> x2 + 3x - 4 = 0
---> x2 - x + 4x - 4 = 0
--> x ( x - 1 ) + 4 ( x - 1 ) = 0
Hence( x - 1 ) ( x + 4 ) = 0
Ultimately the value of x will be 1
Prove ---->
[ 2x + 3 ]^2 = 25
2x + 3 = 5
x = 1
Hope it helps you ☺
★ Here is your answer ★
__________________________
--> [ 2x + 3 ]^2 = 25
----> 4x2 + 9 + 2 [ 2x × 3 ] = 25
---> 4x2 + 9 + 12x - 25 = 0
---> 4x2 + 12x - 16 = 0
---> x2 + 3x - 4 = 0
---> x2 - x + 4x - 4 = 0
--> x ( x - 1 ) + 4 ( x - 1 ) = 0
Hence( x - 1 ) ( x + 4 ) = 0
Ultimately the value of x will be 1
Prove ---->
[ 2x + 3 ]^2 = 25
2x + 3 = 5
x = 1
Hope it helps you ☺
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