plz answer the question number 37
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I hope my ans is correct
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it is a easy question
if two polesPQ&AB are perpendicular to each orher
drwo a parrallel line to the ground which intersect AB tower at c
which means ac+cb=11
cb is equal to the height shorter tower
ac+6=11
ac=5
distance between poles is 12cm
pc is also 12 cm
using pythagoras theorm
pa2=ac2+pc2
=25+144
=169
pa=13cm
pa is the distance between the top of the poles
if two polesPQ&AB are perpendicular to each orher
drwo a parrallel line to the ground which intersect AB tower at c
which means ac+cb=11
cb is equal to the height shorter tower
ac+6=11
ac=5
distance between poles is 12cm
pc is also 12 cm
using pythagoras theorm
pa2=ac2+pc2
=25+144
=169
pa=13cm
pa is the distance between the top of the poles
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