plz answer the questions 1 and 2
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Heya dear user !!!
Here is your answer,
=================================
1.Find the cube root of 4741632 by estimation method.
![\sqrt[3]{4741632} \sqrt[3]{4741632}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B4741632%7D++)
..(II).. ..(I)..
___ ___
4741 632
Group (I) => 632, one place is 2,so cube root of one place is 8
As because in (8)³ = 512 one place is 2
Group (II) => 4741 = 4096 < 4741 < 4913
= (16)³ < 4741 < (17)³
We will take the smaller one = 16
Hence,
![\sqrt[3]{4741632} = 168 \sqrt[3]{4741632} = 168](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B4741632%7D++%3D+168)
=================================
2. Find the volume of a cube whose surface area is 150 m²
Solution :
Surface area of cube = 6×(side)²
=> 6×(side)² = 150
=> (side)² = 150/6
=> (side)² = 25
=> side = √25
=> side = 5
Side of the cube = 5m
Volume of the cube = (side)³
= (5)³
= 5×5×5
= 125m³
=================================
Hope it helps.
Here is your answer,
=================================
1.Find the cube root of 4741632 by estimation method.
..(II).. ..(I)..
___ ___
4741 632
Group (I) => 632, one place is 2,so cube root of one place is 8
As because in (8)³ = 512 one place is 2
Group (II) => 4741 = 4096 < 4741 < 4913
= (16)³ < 4741 < (17)³
We will take the smaller one = 16
Hence,
=================================
2. Find the volume of a cube whose surface area is 150 m²
Solution :
Surface area of cube = 6×(side)²
=> 6×(side)² = 150
=> (side)² = 150/6
=> (side)² = 25
=> side = √25
=> side = 5
Side of the cube = 5m
Volume of the cube = (side)³
= (5)³
= 5×5×5
= 125m³
=================================
Hope it helps.
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