Question

plz answer this .........................

Answer 1

Answer:

x = 1

Step-by-step explanation:

Given: sinθ = (x² + y² + 1)/2x.

= [(x² + y² + 1)/2x] ≤ 1

= x² + y² + 1 ≤ 2x

= x² + y² + 1 - 2x ≤ 0

= x² + 1 - 2x + y² ≤ 0

= (x - 1)² + y² ≤ 0

= (x - 1) = 0, y² = 0

Possible values are:

x = 1, y = 0.

Therefore, the value of x = 1.

Hope it helps!