Question

The magnitude of magnetic field produced by an
infinitely long current carrying conductor at a
perpendicular distance R from the conductor is
Hoi
given by B = 2-R and its direction is given by
right hand thumb rule, where
Ho = Permeability of vacuum (a constant) = 4 11
10-7 Tm/A
B = Magnetic field strength (in tesla)
i = Current flowing in conductor (in ampere)
R = Distance from conductor (in meter)
Then consider a current 10A is flowing in a
straight conductor of infinite length. At what
distance in meters from the wire the magnetic
field will be 5 x 10-71?​

Answer 1

Answer:

using the formula for calculating magnetic field produced by a straight current carrying conductor

$b = uit \div 2\pi \: r$

where u=permeability of vacuum,I=current and T=Tesla

now magnetic field is given

5*10-⁷¹=10*4π*10-⁷÷2πr

cancel pi with pi

r=4*10-⁷*10÷2*5*10-⁷¹

r=4*10⁶⁴m