Question

plz answer this question ​

Answer 1

Step-by-step explanation:

the same question came for my model exam.

Answer 2

Answer and Step-by-step explanation:

cos α÷cos β = m

cos α÷sin β=n

LHS=(m²+n²)cos²β

      = (cos α÷cos β+cos α÷sin β)² cos²β

      = (cos² α (1÷cos² β + 1÷sin² β))cos² β

      = (sin² β + cos² β ÷ cos² β + sin² β)×cos² α + cos² β

using trigonometry identity - sin²A + cos²A =1

      =cos² α × cos² β ÷ cos² β × sin² β

      = cos² α ÷ sin² β

      = (cos α ÷ sin β)²

∴ ( m²+n²)cos² β = n²

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