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semiperimeter =a+b+c/2
=39+25+56/2
=92
Area of ∆= √s(s-a)(s-b)(s-c)
=√92(92-39)(92-25)(92-56)
=√92(53)(67)(36)
=3429.418
=39+25+56/2
=92
Area of ∆= √s(s-a)(s-b)(s-c)
=√92(92-39)(92-25)(92-56)
=√92(53)(67)(36)
=3429.418
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