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area of quare is = (side)^2
so,let side be x
1225/4=x^2
so x= 35/2m
and perimeter is 4*side
so perimeter odf square in this ques is
4*35/2=70
so,let side be x
1225/4=x^2
so x= 35/2m
and perimeter is 4*side
so perimeter odf square in this ques is
4*35/2=70
insiyahr:
The answer is different its 35/2 m perimeter is 70m
Answered by
1
Given that Area of square field = 306 (1/4)
= > 1225/4 m^2.
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We know that Area of square = s^2
= > s^2 = (1225/4)
= > s^2 = (35/2)^2
= > s = (35/2).
Therefore, the length of one side of the field = (35/2)m.
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Now,
We know the perimeter of a square field = 4 * side
= > 4 * (35/2)
= > 2 * 35
= > 70m.
Therefore, the perimeter of a square field = 70m.
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Hope this helps!
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