plz anyone answer ......
class 9th Quadrilateral
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Sol.:-
AB II CD
angle ABP = angle CDQ {alternate angles}
In trinagke APB and triangle CQD,
angle APB = angle CQD (90°)
angle ABP = angle CDQ
AB = CD (opposite side of gem and 2gpad)
triangle APB =~ triangle CQD (AAS property)
AP=CQ
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