Plz can u give the answer of this question . Plz solve the 7th question
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nic
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Answered by
2
angle x =180°-angle ADC(straight angle)
=180°-85°=95°
angle y =180°-(30+85)°(sum of 3 angles of a triangle is 180°)
=180°-115°=65°
angle z +angleABD=angle ADC (exterior angle)
angle z=85°-60°=25°
x=95°
y=65°
z=25°
=180°-85°=95°
angle y =180°-(30+85)°(sum of 3 angles of a triangle is 180°)
=180°-115°=65°
angle z +angleABD=angle ADC (exterior angle)
angle z=85°-60°=25°
x=95°
y=65°
z=25°
Well after reading both answers I am a little confused
Answered by
2
85+30+/_ y=180(A.S.P of a triangle)
=>115+/_ y =180
=>/_y =180-115
=>/_y=65
Now,
Angle x=/_ADC-180(linear pair)
Angle x=85-180
Angle x=95
Again,
/_z+60+/_x=180
/_z=155-180
/_z=25
Hope it helped
=>115+/_ y =180
=>/_y =180-115
=>/_y=65
Now,
Angle x=/_ADC-180(linear pair)
Angle x=85-180
Angle x=95
Again,
/_z+60+/_x=180
/_z=155-180
/_z=25
Hope it helped
60°+95°=155°.... 180°-155°=25° ...z=25°
oh sry typeing mistake
hmm
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