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its n^3
using formula 1+2+3... n= n(n+1)/2
1+2+3...+(n-1) will be (n-1)(n-1+1)/2 = (n-1)n/2
inserting value in equation it becomes
n^2 + 2n × n(n-1)/2
simplify and get n^3
using formula 1+2+3... n= n(n+1)/2
1+2+3...+(n-1) will be (n-1)(n-1+1)/2 = (n-1)n/2
inserting value in equation it becomes
n^2 + 2n × n(n-1)/2
simplify and get n^3
SMB:
thank u!
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