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First angle= (x-40)°
Second angle= (x-20°)
Third angle= (x/2-10)°
(x-40)°+(x-20)°+(x/2-10)°=180° (Angle sum property of a triangle)
x-40+x-20+x/2-10=180°
2x-60-10+x/2=180°
2x-70+x/2=180°
2x+x/2= 180°+70
2x+x/2= 250°
4x/2+x/2=250°
5x/2= 250°
5x= 250×2
5x= 500
x= 500/5
x= 100°
Therefore first angle= (100-40)=60°
Second angle= (100-20)°= 80°
Third angle= (100/2-10)= 50-10= 40°
Second angle= (x-20°)
Third angle= (x/2-10)°
(x-40)°+(x-20)°+(x/2-10)°=180° (Angle sum property of a triangle)
x-40+x-20+x/2-10=180°
2x-60-10+x/2=180°
2x-70+x/2=180°
2x+x/2= 180°+70
2x+x/2= 250°
4x/2+x/2=250°
5x/2= 250°
5x= 250×2
5x= 500
x= 500/5
x= 100°
Therefore first angle= (100-40)=60°
Second angle= (100-20)°= 80°
Third angle= (100/2-10)= 50-10= 40°
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