Math, asked by kingrawat, 1 year ago

plz give full explaination

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Answers

Answered by Madhu123mri
2
First angle= (x-40)°
Second angle= (x-20°)
Third angle= (x/2-10)°

(x-40)°+(x-20)°+(x/2-10)°=180° (Angle sum property of a triangle)

x-40+x-20+x/2-10=180°

2x-60-10+x/2=180°

2x-70+x/2=180°

2x+x/2= 180°+70

2x+x/2= 250°

4x/2+x/2=250°

5x/2= 250°

5x= 250×2

5x= 500

x= 500/5

x= 100°

Therefore first angle= (100-40)=60°

Second angle= (100-20)°= 80°

Third angle= (100/2-10)= 50-10= 40°

Madhu123mri: Sorry it took time for me to do it :(
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