Question

plz give me all answers​

Answer 1

Answer:

(a) 25

(b) 7

(c) The first square number which is greater than 7653 is 88^2 = 7744. 7744–7653=91. So 91 should be added to7653 to make it a perfect square.

Answer 2

Answer:

$a) \: \: \: {5}^{2} = 25 \\ \\ b) \: \: \: \sqrt[3]{343} = 7 \\ \\ c) \: \: \: 91 + 9 = 100 \\ 100 = {10}^{2} \\ \\ d) \: \: \: 36 = {6}^{2} \\ 36 \times 6 = 216 \\ 216 = \sqrt[3]{6} \\ number \: \: is \: \: 6 \\ \\ e) \: \: \: {a}^{2} - {b}^{2} = (a + b)(a - b) \\ \\ f) \: \: \: HCF(16, \: \: 36, \: \: 20) = 4 \\ \\ h) \: \: \: x \: \: will \: \: be \: \: 0 \: \: or \: \: 5 \\ \\ i) \: \: \: LCM(15, \: \: 6, \: \: 10) = 30 \\ \\ j) \: \: \: 30 = 2 \times 3 \times 5 \\ All \: \: the \: \: factors \: \: are \: \: prime \: \: numbers \\ \\ k) \: \: \: 1, \: \: 2, \: \: 3, \: \: 5, \: \: 6, \: \: 10, \: \: 15, \: \: 30 \\ \\ m) \: \: \: 28 {x}^{4} \div 7x \\ \frac{28 {x}^{4} }{7x} \\ = \frac{4 \times \cancel 7 \times x \times \cancel x \times x \times x}{ \cancel 7 \times \cancel x} \\ = 4 {x}^{3} \\ \\ n) \: \: \: 6abc = 2 \times 3 \times a \times b \times c \\ 9 {a}^{2} bc =3 \times 3 \times a \times a \times b \times c \\ 15bc = 3 \times 5 \times b \times c \\ Common \: \: Factor \: \: is :3bc \\ \\p) \: \: \: {a}^{2}+8a+16 \\ {a}^{2} + 4a + 4a + 16 \\ a (a + 4) + 4 (a + 4) \\ (a+ 4) (a + 4) \\ \\ r) \: \: \: False \\ \\ s) \: \: \: True \\ \\ t) \sqrt{4489}=67 \\ Number \: \: of \: \: digits \: \: are \: \: 2$