Question

plz give me answer of the question

Answer 1

complex numbers 

 i = $\sqrt{-1}$
so,
      $(- \sqrt{-1} ) ^{4n+3}$

     $(-( i )) ^{4n+3}$

     it is to the power 4n+3 for which when divide by 4 always gives a reminder 3 for any natural number vale for n 

which will result as

$(-i) ^{3} = - ( -i)$

$= i$

$= \sqrt{-1}$

answer is $\sqrt{-1}$