Question

plz give me answer on paper and send me

Answer 1

• Let the no. of 1 rupee coin be 3 x

                      ''         50 paise    ''     4 x

             and            ''  25 paise     ''   5 x          

A/q.  3 x × 1 + 4 x × 1/2  + 5 x × 1/4 = 200

   ⇒ 3x + 2x + 5x/4 = 200

  ⇒ 25x/4 = 200

 ⇒ x  = 4 × 8 = 32.

No. of 1 rupee coin = 3x = 3 x 32 = 96

''        ''  50 paise '' '= 4 x  = 4 x 32 = 128

''      ''   25   ''           ''  = 5 x = 5  x  32 =  160

Thank u.

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