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I'LL MARK THE BEST ANSWER AS BRAINLIEST Which are the zeroes of p(x)=(x-1)(x-2)
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Answer:
x=2,1
Step-by-step explanation:
p(x)=(x-1)(x-2)
x^2-2x-x+2
x^2-3x+2
x^2-2x-1x+2=0
x(x-2)-1(x-2)=0
x-2=0,x-1=0
x=2,x=1
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