plz give the answer mathematics
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use formula of cos2a and sin2a.
cot(a/2) = 2/3.
so cos(a/2) = 2/(13)^1/2
again use formula of cos2a.
cos a = -5/13.
sin a = 12/13.
cosec a = 13/12.
cot a = - 5/12.
cot(a/2) = 2/3.
so cos(a/2) = 2/(13)^1/2
again use formula of cos2a.
cos a = -5/13.
sin a = 12/13.
cosec a = 13/12.
cot a = - 5/12.
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