Question

Plz help me for this question

Answer 1

Answer:

sorry I have not learned it yet.

Answer 2

Answer:

$\textbf{Given:} \: \tan A = \frac{4}{3}$

$\textbf{To Find:} \: \sin A \: \textbf{and} \: \cos A$

$\sf \colorbox{pink} {We Know}$

$⇒ \tan A = \frac{4}{3} = \frac{opposite}{adjective}$

[∴look at the pic]

$⇒AC = \sqrt{( CA {)}^{2} + (AB {)}^{2} }$

$⇒BC = \sqrt{ {3}^{2} + {4}^{2} } = 5$

$⇒BC = 5$

$⇒ \sin A = \frac{opposite}{hypotenus} = \frac{4}{5}$

$⇒ \sin A = \frac{adjacent}{hypotenus} = \frac{3}{5}$

$\textbf{Hence we Get}$

$\sin A = \frac{4}{5} , \cos A = \frac{3}{5}$

$\\ \\ \\ \\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$