Question

plz help me
in my revision papewr

Answer 1

Answer:

[Solution

Given :-

Height of two poles 6 m and 11m

Distance between their feet 12m

Find :-

Distance between their top

Explanation

Let,

AB is first pole & CD is second pole there height be 6m & 11m ,

and,

Distance between BD is 12m ,

So,Now we ,

Drop a line AC and a other line AE in CD , parallel to BD.

So, by figure ,

BD = AE = 12m

AB = ED = 6m

And,

CE = CD - ED

==> CE = 11 - 6 = 5 m

So we take a right ∆AEC,

Where,

Hypotenuse = AC = ?

Base = AE = 12m

Perpendicular = CE = 5 m

Using Pythagoras's Theorem ,

★ (Hypotenuse)² = (Base)² + (perpendicular)²

==> AC² = 12² + 5²

==> AC² = 144 + 25

==> AC² = 169

==> AC = √169

==> AC = 13

Hence

Distance between their top of pole will be AC = 13 m

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Solution

Given :-

A triangle has a perimeter 20.0 1 cm

two sides are 6.38 cm and 5.0 67 cm

Find :-

Third Side of triangle

Step - by - Step - Explanation

Using Formula

★ Perimeter of triangle = Sum of all side .

So, Let

Third Side of triangle be x cm

Assume that, ∆ABC ,

Where,

AB = 6.38 cm

BC = 5.067 cm

CA = x cm

So,

==> perimeter of triangle = AB + BC + CA

==> 20.01 = 6.38 + 5.067 + x

==> 20.01 = 11.447 + x

==> x = 20.01 - 11.447

==> x = 8.563 cm

Hence

Third Side of triangle ∆ABC will be CA(x) = 8.563 cm

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