plz help me slove it
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110°= [(2x-20)°+(x-10)°]
(exterior angle= sum of opposite interior angles)
110° = 2x-20+x-10
110° = 3x-30
110°+30 = 3x
140° = 3x
x= (140°/3)
x= 46.66°
hope this helps you
(exterior angle= sum of opposite interior angles)
110° = 2x-20+x-10
110° = 3x-30
110°+30 = 3x
140° = 3x
x= (140°/3)
x= 46.66°
hope this helps you
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