plz help me..... solve Q 23.....
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In triangle ADC and AEB,
Angle A=Angle A(common)
AD=AE(given)
AC=AB(since AE+CE=AD+BD)
Therefore, triangle ADC is congruent to triangle AEB
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Angle A=Angle A(common)
AD=AE(given)
AC=AB(since AE+CE=AD+BD)
Therefore, triangle ADC is congruent to triangle AEB
Solved
luthfur069:
can u tell me it is which congruency.
SAS congruency
thanks
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This same solution was sended before still see in attach file
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