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From an external point P two tangents PA and PB are drawn to the circle with centre O. prove that OP is the perpendicular bisector of AB.
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In∆OAP and ∆OBP ,
OP=OP
PA=PB
Therefore,∆OAP=∆OBP
SO,OP is the perpendicular bisector of AB
OP=OP
PA=PB
Therefore,∆OAP=∆OBP
SO,OP is the perpendicular bisector of AB
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sujit can u help me with my other math problem
i posted already
Ya sure..if u want i can also help
A television is available for Rs. 7500 cash or Rs. 3000 cash down payment followed by five equal monthly instalments of Rs. 1000 each. Find the rate of interest per annum charged under the instalment plan.
sry ...i can't
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