Question

plz mate answer me plz plz plz plz plz plz plz pl​

Answer 1

Here is your answer user.

Answer 2

6answer).

Let, produce ray OQ backward T.

angle TOP+angle POQ=180°———(eq.1)

(linear pair)

angle TOS+angle SOR+ROQ=180°———(eq.2)(linear pair)

add eq.(1)and(2)

angle TOP+angle POQ+angle TOS+angle SOR+angle ROQ=360°

therefore, POQ+angle POS+angle SOR+angle QOR=360°

7answer).

angle APQ=angle RQP(alternate angle)

angle RQP=50°

x=50°

angle PRD+angle PRQ=180°(linear pair)

127°+angle PRQ=180°

angle PRQ=180°-127°

angle PRQ=163°

angle QPR+angle PQR+angle RQP=180°

(property of triangle)

angle QPR+angle PQR+angle RQP=180°

angle QPR+113°=180°

angle QPR=67°

y=67°

8answer).

suppose y=3a

z=7a

angle NOC+angle OZF=180°(linear pair)

3a+7a=180°

10a=180°

a=180°\10

a=18°

y=3a=3(18°)=54°

z=7a=7(18°)=126°

angle X=angle Y(alternate angle)

angle X=126°

9answer).

angle XPB=angle APQ(alternate angle)

angle APQ=75°

angle APA=angle PQD(alternate angle)

angle PQD=75°

angle PQD=angle CQY(vertically opposite angle)

hope it is helpful...

please mark as brainliest....

angle CQY=75°