Question

Plz... Plz... Find range.... ​

Answer 1

Answer:

All real numbers except zero.

Step-by-step explanation:

Let f(x) = y

y = 1/√5-x

Squaring,

y^2 = 1/5-x

5-x = 1/y^2

x = 5 - 1/y^2

x = (5y^2-1)/y^2

y^2 ≠ 0

y≠0

So range of f(x) = all real numbers except 0

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Answer 2

Answer:

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