Question

plz say the answer. maths .,.if you are good at mathamatics

Answer 1

heya,

it'd too easy .

x^2-4x+3=0

=x^2-3x-x+3=0
=x(x-3)-1(x-3)=0
=(x-1)(x-3)=0 x=1 and x=3

let it's two zero alpha and bita
where alpha =1 and bita =3


for finding relation between it's cofficient an zero.

now , -cofficient of x/cofficient of x^2=sum of all zero

-cofficient of x/cofficient of x^2 = sum of all zero.

where ,
cofficient of x=4 and cofficient of x^2=1

and sum of its zero =3+1=4

=)-(-4)/1=3+1
4=4

and similarly relation between it's product and cofficient is

product of zero =constant term /cofficient of x^2
=)3=3/1

3=3

hope it help you .

@rajukumar.