Question

plz say this answer bczz tomorrow my exams are there

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Answer 1

Answer:

${x}^{2} - 4\sqrt{2}x + 6 = 0$

${x}^{2} - 4 \sqrt{2} x = - 6$

$\frac{1}{2} \times coefficient \: of \: x$

$\frac{1}{2} \times - 4 \sqrt{2}$

$( - 2 \sqrt{2} ) ^{2}$

${x}^{2} - 4 \sqrt{2} x + ( {- 2 \sqrt{2}} ^{2} ) = - 6 - 2 \sqrt{2} ^{2}$

$(x - 8)^{2} = - 6 + 8$

$(x - 8) ^{2} = 2$

$x - 8 = + - \sqrt{2}$

$x - 8 = \sqrt{2} \: or \: x - 8 = - \sqrt{2}$

$x = 8 + \sqrt{2} \: or \: x = 8 - \sqrt{2}$

$x = 8 + \sqrt{2} \: or \: 8 - \sqrt{2}$

Hope it helps...

Mark as branliest...

Answer 2

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Please yaar krdo vapis id password bta day yaar koi kutch ni bolay ga tumhay