Question

plz.. solve 1(¡¡¡).............

Answer 1

867 and 225

since 867 > 255 we apply the division lemma to 867 ant 255 to obtain

867=255×3+102 n

since remainder 102 is not equal to 0 we apply the division lemma to 255 and 102 to obtain

255=102×2+51


we consider the new divisior 102 and new remainder 51 and apply the division lemma to obtain

102= 51×2+0

since the remainder is 0 the process stops.

since the divisor at the stage is 51

therefore hcf of 867 and 255 is 51

HOPE IT'S HELP YOU ☺

Answer 2

this is division method... very simple..