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anshu4952:
wrong
ans 80
i am sorry
at last
11 ki jagah 8 aayega
tab answrr sahi a jayega
jaldbaji m ho gaya
i am really sorry
ok
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Easy
We need to find 25th term
Let the sum of n terms be given by Sn
so
Sn = 3n²/2+ 5n/2
S1 = 3(1)²/2 + 5(1)/2
= 3/2+5/2 => 4
so 1st term is 4 say 'a'
Now
S2 = 3(2)²/2 + 5(2)/2
= 6+5 => 11
Now a2 = S2 - a1
=> a2 = 11-4 = 7
Now common difference (d)
= a2-a1 => 7-4 = 3
we know
an = a+(n-1) d
so
a25 = 4 + (25-1)(3)
=> a25 = 4 + 24×3 =>4+ 72
so 25th term of the AP is 76.
Hope this helps you
Please mark as brainliest
We need to find 25th term
Let the sum of n terms be given by Sn
so
Sn = 3n²/2+ 5n/2
S1 = 3(1)²/2 + 5(1)/2
= 3/2+5/2 => 4
so 1st term is 4 say 'a'
Now
S2 = 3(2)²/2 + 5(2)/2
= 6+5 => 11
Now a2 = S2 - a1
=> a2 = 11-4 = 7
Now common difference (d)
= a2-a1 => 7-4 = 3
we know
an = a+(n-1) d
so
a25 = 4 + (25-1)(3)
=> a25 = 4 + 24×3 =>4+ 72
so 25th term of the AP is 76.
Hope this helps you
Please mark as brainliest
wrong
ans 80
will do it please wait
76 is the answer
it is wrong
ya check 76 is the correct answer
Dam sure
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