plz solve as soon as possible..........
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b) 40.8eVis the answer
Tanaya62:
The answer is (d).......
still.... thanks for your instant answer
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13.6ev×9=122.4ev .....the ans is (d) 122.4ev....
can you explain it in detail....????!!!!!
Ya ofcourse☺......IE = 13.6Z²/n² eV
Where Z is atomic number and n is the shell number.
In this case Z is 3 and n is 1( because hydrogen is having n=1)
So IE Li²+ = 13.6×9 = 122.4 eV.
Where Z is atomic number and n is the shell number.
In this case Z is 3 and n is 1( because hydrogen is having n=1)
So IE Li²+ = 13.6×9 = 122.4 eV.
You are satisfying or not???
yeah..... thanks a lot..... ^_^
My pleasure !!!!! yrrr
Hello tanaya how's you??
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