Question

Plz solve
Class 09
Thanks in advance

Answer 1

$\huge\mathbb\pink{Answer}$

Let atomic mass of element A be =a g/mol
Again atomic mass of Oxygen =16 g/mol

So molar mass of the compound A2O3=(2a+48) g/mol
One molecule of the compound A2O3 contains 2 atoms .

So the ratio of mass of AandA2O3 in a molecule 
2a2a+48

Again it is given that 0.359 grams of A reacts to give 0.559 grams of the compound. So we can write

2a2a+48=0.3590.559

⇒aa+24=359559

⇒1+24a=559359=1.55

⇒24a=0.55

⇒a=240.55=43.6 amu