Math, asked by shuvechchha32, 1 year ago

plz solve it .........​

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shuvechchha32: plz help me to solve it

Answers

Answered by priyabachala
3

given,

CP1 + CP2 = 6000/-

CP2 = 6000-CP1

and

20/100 = (SP1-CP1)/CP1

1/5 = (SP1-CP1)/CP1

CP1 = 5SP1-5CP1

6CP1 = 5SP1

SP1 = 6/5(CP1) ............(1)

10/100 = (CP2-SP2)/CP2

1/10 = (CP2-SP2)/CP2

CP2 = 10CP2-10SP2

9CP2 = 10SP2

SP2 = 9/10(CP2)

= 9/10(6000 -CP1)

= 5400-9/10(CP1)............(2)

AND,

2/100 = (SP1+SP2)-(CP1+CP2)/ (CP1+CP2)

1/50 = [6/5(CP1)+5400-9/10(CP1)]-(6000)/6000

1/50 =[3/10(CP1)+5400-6000]/6000

1/50 = [3/10(CP1)-600]/6000

6000 = 15(CP1)-30000

15(CP1) = 36000

CP1 = 2400

CP2 = 6000-2400 = 3600

SO, two radios are brought at 2400 and 3600 rupees

Pls mark as brainlist


shuvechchha32: tq
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