Question

plz solve it fast tmrw exam I'll mark brainlest

Answer 1

Given LHS:

$1 + \frac{cot^2theta}{1 + cosec theta}$

We know that 1 + cot^2theta = cosec^2theta-1

$1 + \frac{cosec^2theta - 1}{1 + cosectheta}$

We know that a^2 - b^2 = (a + b)(a - b)

$1 + \frac{(cosectheta+1)(cosectheta-1)}{(cosectheta+1)}$

1 + cosectheta - 1

cosec theta.

LHS = RHS



Hope this helps!

Answer 2

the answers to your question