Question

plz solve it in an easy and short method..

Answer 1

Let the rhombus be ABCD and let there diameters intersect each other at O.
Since,in a Rhombus all sides are equal,
Therefore AB=AD
and since ABCD is rhombus therefore its diagonals bisect each other
So,AO=DO
and
AO=AO(common)
Therefore 
ΔABO=~ΔADO
Similarly,ΔABO=~ΔBCO
Similarly,
ΔBCO=~ΔDCO
Therefore 
ΔABO=~ΔBCO=~ΔCDO=~ΔADO
HOPE HELPS....